What is Trigonometry?

Trigonometric ratios are right-angled triangle functions that show the relationship between angles and sides.
Topics Trigonometry Covers
The following are the topics trigonometry covers:
- Right Triangle Trigonometry
- Unit Circle
- Graphs of Trig Functions
- Trigonometric Identities
- Inverse Trig Functions
- Solving Triangles
- Trigonometric Equations
- Real World Applications
What Skills Does Trigonometry Develop?
Trigonometry in Mathematics develops core skills like problem-solving abilities, logical and analytical thinking, a strong foundation of advanced mathematics, critical thinking, and spatial reasoning.
What are Trigonometric Ratios?
If we have a right-angle triangle, the length of each side of the triangle tells how steep or wide the given angle is, and trigonometric ratios are the simple comparison of those side lengths of the angle.
The basic trigonometric ratios include sine, cosine, and tangent.
However, other trigonometric ratios include cosec, sec, and cot.
How to Find Trigonometric Ratios?
In a right-angle triangle (an angle = 90°), find out
- Opposite: The side opposite to θ
- Adjacent: The side next to θ
- Hypotenuse: The side always opposite the right angle
Identifying adjacent, opposite and hypotenuse will help you find trigonometric ratios.
Trigonometric Ratio Formulas

sin θ = opposite/hypotenuse
cos θ = adjacent/hypotenuse
tan θ = opposite/adjacent
For Example
In the above given right-angle triangle
c = Hypotenuse = 5
a = Opposite = 3
b = Adjacent = 4
The trigonometric ratios for the above right-angle triangle will be
sin (37°) = opposite/hypotenuse = 3/5
cos (37°) = adjacent/hypotenuse = 4/5
tan θ = opposite/adjacent = 3/4
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SOH-CAH-TOA Technique
SOH-CAH-TOA is a simple way to learn how to memorize trigonometric ratios without confusion.
- SOH means: Sine = Opposite / Hypotenuse
- CAH means: Cosine = Adjacent / Hypotenuse
- TOA means: Tangent = Opposite / Adjacent
How to Find Trigonometric Ratios?
Besides the core three sine, cosine and tangent, other trigonometric ratios include Cotangent, Secant, and Cosecant.
As we know how to find hypotenuses, perpendicular or opposite (same), and adjacent, it will be easy to find all trig ratios.
The following are the formulas to find other trigonometric ratios.
- Sine = sin θ = opposite/hypotenuse
- Cosine = cos θ = adjacent/hypotenuse
- Tangent = tan θ = opposite/adjacent
- Cosecant = cscθ = Hypothesis/Opposite
- Secant = secθ =Hypothesis/Adjacent
- Cotangent = cot θ = Adjacent/Opposite
For Example
In Figure 1.2, the given sides are
Hypotenuse = 5
Opposite = 3
Adjacent = 4
So the trigonometry ratios will be
sin θ = opposite/hypotenuse = 3/5
cos θ = adjacent/hypotenuse = 4/5
tan θ = opposite/adjacent = 3/4
cscθ = Hypothesis/Opposite = 5/3
secθ = Hypothesis/Adjacent = 5/4
cot θ = Adjacent/Opposite = 4/3
All Trigonometric Ratios Formulas
Below is a cleaner look at all trigonometric ratios with their formulas. Students can practice using a trigonometric ratios formula worksheet to strengthen their understanding.

Trigonometric Ratios Table
Below is the trigonometric ratios table with respect to angles 0°, 30°, 45°, 60°, and 90°.
| θ (degrees) | sin θ | cos θ | tan θ | cosec θ | sec θ | cot θ |
|---|---|---|---|---|---|---|
| 0° | 0 | 1 | 0 | Not defined | 1 | Not defined |
| 30° | 1/2 | √3/2 | 1/√3 | 2 | 2/√3 | √3 |
| 45° | 1/√2 | 1/√2 | 1 | √2 | √2 | 1 |
| 60° | √3/2 | 1/2 | √3 | 2/√3 | 2 | 1/√3 |
| 90° | 1 | 0 | Not defined | 1 | Not defined | 0 |
Trigonometric Identities
Trigonometric identities are true for every value of the variable recurring on both sides of the expression or equation. Trigonometric identities involve all trigonometric functions (sine, cosine, tangent, secant, cosecant, and cotangent.
Trigonometric identities include:
- sin²θ + cos²θ = 1
- 1 + tan²θ = sec²θ
- 1 + cot²θ = cosec²θ
- tan θ = sin θ / cos θ
- cot θ = cos θ / sin θ
Difference Between Trig Ratios and Trig Identities
| Trigonometric Ratios | Trigonometric Identities |
|---|---|
| Defined using triangle sides | Equations always true |
| Depend on a right-angled triangle | Independent of the triangle |
| Used to find values | Used to simplify & prove |
| Example: sin θ = opp/hyp | Example: sin²θ + cos²θ = 1 |
Fundamental Trigonometric Identities
Below are common trigonometric identities used to solve complex maths problems.
Reciprocal Identities
- sin θ = 1 / cosec θ
- cosec θ = 1 / sin θ
- cos θ = 1 / sec θ
- sec θ = 1 / cos θ
- tan θ = 1 / cot θ
- cot θ = 1 / tan θ
Quotient Identities
- tan θ = sin θ / cos θ
- cot θ = cos θ / sin θ
Pythagorean Trig Identities
- sin²θ + cos²θ = 1
- 1 + tan²θ = sec²θ
- 1 + cot²θ = cosec²θ
Double-Angle Trigonometric Identities
Sine
- sin 2θ = 2 sin θ cos θ
Cosine
- cos 2θ = cos²θ − sin²θ
- cos 2θ = 1 − 2 sin²θ
- cos 2θ = 2 cos²θ − 1
Tangent
- tan 2θ = 2 tan θ / (1 − tan²θ)
Cotangent
- cot 2θ = (cot²θ − 1) / (2 cot θ)
Half-Angle Trigonometric Identities
Sine
- sin(θ/2) = ± √[(1 − cos θ) / 2]
Cosine
- cos(θ/2) = ± √[(1 + cos θ) / 2]
Tangent
- tan(θ/2) = ± √[(1 − cos θ) / (1 + cos θ)]
- tan(θ/2) = (1 − cos θ) / sin θ
- tan(θ/2) = sin θ / (1 + cos θ)
Cotangent
- cot(θ/2) = ± √[(1 + cos θ) / (1 − cos θ)]
- cot(θ/2) = (1 + cos θ) / sin θ
- cot(θ/2) = sin θ / (1 − cos θ)
Sum and Difference Trigonometric Identities
Sine
- sin(A + B) = sin A cos B + cos A sin B
- sin(A − B) = sin A cos B − cos A sin B
Cosine
- cos(A + B) = cos A cos B − sin A sin B
- cos(A − B) = cos A cos B + sin A sin B
Tangent
- tan(A + B) = (tan A + tan B) / (1 − tan A tan B)
- tan(A − B) = (tan A − tan B) / (1 + tan A tan B)
Product-to-Sum Trigonometric Identities
Sine × Sine
- sin A sin B = ½ [cos(A − B) − cos(A + B)]
Cosine × Cosine
- cos A cos B = ½ [cos(A − B) + cos(A + B)]
Sine × Cosine
- sin A cos B = ½ [sin(A + B) + sin(A − B)]
- cos A sin B = ½ [sin(A + B) − sin(A − B)]
Sum-to-Product Identities
Sine
- sin A + sin B = 2 sin((A + B)/2) cos((A − B)/2)
- sin A − sin B = 2 cos((A + B)/2) sin((A − B)/2)
Cosine
- cos A + cos B = 2 cos((A + B)/2) cos((A − B)/2)
- cos A − cos B = −2 sin((A + B)/2) sin((A − B)/2)
Triple-Angle Identities
Sine
- sin 3θ = 3 sin θ − 4 sin³θ
Cosine
- cos 3θ = 4 cos³θ − 3 cos θ
Tangent
- tan 3θ = (3 tan θ − tan³θ) / (1 − 3 tan²θ)
Power-Reduction (Reduction) Identities
- sin²θ = (1 − cos 2θ) / 2
- cos²θ = (1 + cos 2θ) / 2
- tan²θ = (1 − cos 2θ) / (1 + cos 2θ)
Co-Function Identities
- sin(90° − θ) = cos θ
- cos(90° − θ) = sin θ
- tan(90° − θ) = cot θ
- sec(90° − θ) = cosec θ
- cosec(90° − θ) = sec θ
- cot(90° − θ) = tan θ
Negative-Angle Identities
- sin(−θ) = −sin θ
- cos(−θ) = cos θ
- tan(−θ) = −tan θ
Periodic Identities
- sin(θ + 2π) = sin θ
- cos(θ + 2π) = cos θ
- tan(θ + π) = tan θ
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Trigonometry Solved Questions Samples
Question 1: Find the value
If sin θ = 3/5, where θ is acute, find cos θ and tan θ.
Solution:
Given:
sin θ = Opposite / Hypotenuse = 3/5
So:
Opposite = 3
Hypotenuse = 5
Using Pythagoras:
Adjacent = √(5² − 3²)
Adjacent = √(25 − 9) = √16 = 4
Now:
- cos θ = Adjacent / Hypotenuse = 4/5
- tan θ = Opposite / Adjacent = 3/4
Answer:
cos θ = 4/5
tan θ = 3/4
Question 2: Evaluate
sin 30° + cos 60°
Solution:
We know:
sin 30° = 1/2
cos 60° = 1/2
So:
sin 30° + cos 60° = 1/2 + 1/2 = 1
Answer: 1
Question 3: Prove that
(1 − cos 2θ) / sin 2θ = tan θ
Solution:
(1 − cos 2θ) / sin 2θ
= (2 sin²θ) / (2 sin θ cos θ)
= sin θ / cos θ
= tan θ
Hence Proved
Question 4: Evaluate
sin θ / (1 + cos θ) + (1 + cos θ) / sin θ
Solution:
sin θ / (1 + cos θ) + (1 + cos θ) / sin θ
= sin²θ / (sin θ(1 + cos θ)) + (1 + cos θ)² / (sin θ(1 + cos θ))
= (sin²θ + (1 + cos θ)²) / (sin θ(1 + cos θ))
= (sin²θ + (1 + 2 cos θ + cos²θ)) / (sin θ(1 + cos θ))
= ((sin²θ + cos²θ) + 1 + 2 cos θ) / (sin θ(1 + cos θ))
= (1 + 1 + 2 cos θ) / (sin θ(1 + cos θ))
= 2(1 + cos θ) / (sin θ(1 + cos θ))
= 2 / sin θ
= 2 cosec θ
Question 4: Evaluate
Simplified Identity
Find the value of 9 csc^2θ − 9 cot^2θ.
Solution:
Factor out 9:
9(csc^2θ − cot^2θ)
Using the identity:
1 + cot^2θ = csc^2θ
So,
csc^2θ − cot^2θ = 1
Therefore:
9(1) = 9
Trigonometry Sample MCQs
- If sin θ = 3/5, where θ is acute, what is cos θ?
- A) 3/4
- B) 4/5
- C) 5/3
- D) 5/4
Correct Answer: B) 4/5
- Evaluate: sin 30° + cos 60°
- A) 0
- B) 1/2
- C) 1
- D) 2
Correct Answer: C) 1
- Which of the following is equal to 1 + tan²θ?
- A) cosec²θ
- B) sec²θ
- C) cot²θ
- D) sin²θ
Correct Answer: B) sec²θ
- Find the value of: (sec θ − tan θ)(sec θ + tan θ)
- A) 0
- B) 1
- C) sec²θ
- D) tan²θ
Correct Answer: B) 1
- Evaluate: sin 2θ / (1 + cos 2θ)
- A) sin θ
- B) cos θ
- C) tan θ
- D) cot θ
Correct Answer: C) tan θ
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Mastering Trigonometry Made Easy
Trigonometry may seem challenging at the beginning, but with practice and the right steps, it becomes much easier to understand.
By learning trigonometric ratios, formulas, and identities, students can solve many math problems quickly and correctly.
Remember to practice regularly, use shortcuts like SOH-CAH-TOA, and understand each step instead of memorising blindly.
With time and practice, mastering trigonometric ratios will feel simple and rewarding.




















